(y+7)(2)=2y(2)+8y+42

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Solution for (y+7)(2)=2y(2)+8y+42 equation:



(y+7)(2)=2y(2)+8y+42
We move all terms to the left:
(y+7)(2)-(2y(2)+8y+42)=0
We add all the numbers together, and all the variables
-(+2y^2+8y+42)+(y+7)2=0
We multiply parentheses
-(+2y^2+8y+42)+2y+14=0
We get rid of parentheses
-2y^2-8y+2y-42+14=0
We add all the numbers together, and all the variables
-2y^2-6y-28=0
a = -2; b = -6; c = -28;
Δ = b2-4ac
Δ = -62-4·(-2)·(-28)
Δ = -188
Delta is less than zero, so there is no solution for the equation

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