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X-1-3(5-2X)=(2X-5)
We move all terms to the left:
X-1-3(5-2X)-((2X-5))=0
We add all the numbers together, and all the variables
X-3(-2X+5)-((2X-5))-1=0
We multiply parentheses
X+6X-((2X-5))-15-1=0
We calculate terms in parentheses: -((2X-5)), so:We add all the numbers together, and all the variables
(2X-5)
We get rid of parentheses
2X-5
Back to the equation:
-(2X-5)
7X-(2X-5)-16=0
We get rid of parentheses
7X-2X+5-16=0
We add all the numbers together, and all the variables
5X-11=0
We move all terms containing X to the left, all other terms to the right
5X=11
X=11/5
X=2+1/5
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