(y+4)/5=(y-2)/3

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Solution for (y+4)/5=(y-2)/3 equation: 



(y+4)/5=(y-2)/3

We move all terms to the left:

(y+4)/5-((y-2)/3)=0

We calculate fractions


y/()+(-((y-2)*5)/()=0



We calculate terms in parentheses: +(-((y-2)*5)/(), so:

-((y-2)*5)/(

We multiply all the terms by the denominator


-((y-2)*5)



We calculate terms in parentheses: -((y-2)*5), so:

(y-2)*5

We multiply parentheses

5y-10

Back to the equation:

-(5y-10)



We get rid of parentheses

-5y+10

Back to the equation:

+(-5y+10)



We get rid of parentheses

y/()-5y+10=0

We multiply all the terms by the denominator


y-5y*()+10*()=0

We add all the numbers together, and all the variables

y-5y*()=0

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