1/5(a+2)=1/6(7-a)

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Solution for 1/5(a+2)=1/6(7-a) equation: 



1/5(a+2)=1/6(7-a)

We move all terms to the left:

1/5(a+2)-(1/6(7-a))=0



Domain of the equation: 5(a+2)!=0

a∈R





Domain of the equation: 6(7-a))!=0

a∈R



We add all the numbers together, and all the variables

1/5(a+2)-(1/6(-1a+7))=0

We calculate fractions


(6a(-)/(5(a+2)*6(-1a+7)))+(-5aa/(5(a+2)*6(-1a+7)))=0



We calculate terms in parentheses: +(6a(-)/(5(a+2)*6(-1a+7))), so:

6a(-)/(5(a+2)*6(-1a+7))

We add all the numbers together, and all the variables

6a0/(5(a+2)*6(-1a+7))

We multiply all the terms by the denominator


6a0

We add all the numbers together, and all the variables

6a

Back to the equation:

+(6a)





We calculate terms in parentheses: +(-5aa/(5(a+2)*6(-1a+7))), so:

-5aa/(5(a+2)*6(-1a+7))

We multiply all the terms by the denominator


-5aa

Back to the equation:

+(-5aa)



We get rid of parentheses

6a-5aa=0

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