(y+1)+(y-4)+(y-2)=0

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Solution for (y+1)+(y-4)+(y-2)=0 equation: 



(y+1)+(y-4)+(y-2)=0

We get rid of parentheses

y+y+y+1-4-2=0

We add all the numbers together, and all the variables

3y-5=0

We move all terms containing y to the left, all other terms to the right

3y=5

y=5/3

y=1+2/3

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