8=4u+(u-2)

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Solution for 8=4u+(u-2) equation: 



8=4u+(u-2)

We move all terms to the left:

8-(4u+(u-2))=0



We calculate terms in parentheses: -(4u+(u-2)), so:

4u+(u-2)

We get rid of parentheses

4u+u-2

We add all the numbers together, and all the variables

5u-2

Back to the equation:

-(5u-2)



We get rid of parentheses

-5u+2+8=0

We add all the numbers together, and all the variables

-5u+10=0

We move all terms containing u to the left, all other terms to the right

-5u=-10

u=-10/-5

u=+2

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