(x2+3x)/(x2-4)=0

Solution for (x2+3x)/(x2-4)=0 equation:

(x2+3x)/(x2-4)=0


Domain of the equation: (x2-4)!=0

We move all terms containing x to the left, all other terms to the right

x2!=4

x^2!=4/

x^2!=√1/0

x!=1

x∈R


We add all the numbers together, and all the variables

(+x^2+3x)/(+x^2-4)=0

We multiply all the terms by the denominator


(+x^2+3x)=0

We get rid of parentheses

x^2+3x=0

a = 1; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·1·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*1}=\frac{-6}{2}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*1}=\frac{0}{2}
=0
$