6(3x-1)-30=3(2x-4)

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Solution for 6(3x-1)-30=3(2x-4) equation: 



6(3x-1)-30=3(2x-4)

We move all terms to the left:

6(3x-1)-30-(3(2x-4))=0

We multiply parentheses

18x-(3(2x-4))-6-30=0



We calculate terms in parentheses: -(3(2x-4)), so:

3(2x-4)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

18x-(6x-12)-36=0

We get rid of parentheses

18x-6x+12-36=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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