(x2+3)2+21=10x2+30

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Solution for (x2+3)2+21=10x2+30 equation: 



(x2+3)2+21=10x^2+30

We move all terms to the left:

(x2+3)2+21-(10x^2+30)=0

We add all the numbers together, and all the variables

(+x^2+3)2-(10x^2+30)+21=0

We multiply parentheses

2x^2-(10x^2+30)+6+21=0

We get rid of parentheses

2x^2-10x^2-30+6+21=0

We add all the numbers together, and all the variables

-8x^2-3=0

a = -8; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-8)·(-3)
Δ = -96
Delta is less than zero, so there is no solution for the equation

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