6(n+2)=9n-21

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Solution for 6(n+2)=9n-21 equation: 



6(n+2)=9n-21

We move all terms to the left:

6(n+2)-(9n-21)=0

We multiply parentheses

6n-(9n-21)+12=0

We get rid of parentheses

6n-9n+21+12=0

We add all the numbers together, and all the variables

-3n+33=0

We move all terms containing n to the left, all other terms to the right

-3n=-33

n=-33/-3

n=+11

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