(x/5+4x)+3(x-5)=

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Solution for (x/5+4x)+3(x-5)= equation: 



(x/5+4x)+3(x-5)=

We move all terms to the left:

(x/5+4x)+3(x-5)-()=0



Domain of the equation: 5+4x)!=0

We move all terms containing x to the left, all other terms to the right

4x)!=-5

x!=-5/1

x!=-5

x∈R



We add all the numbers together, and all the variables

(+4x+x/5)+3(x-5)-()=0

We add all the numbers together, and all the variables

(+4x+x/5)+3(x-5)=0

We multiply parentheses

(+4x+x/5)+3x-15=0

We get rid of parentheses

4x+x/5+3x-15=0

We multiply all the terms by the denominator


4x*5+x+3x*5-15*5=0

We add all the numbers together, and all the variables

x+4x*5+3x*5-75=0

Wy multiply elements

x+20x+15x-75=0

We add all the numbers together, and all the variables

36x-75=0

We move all terms containing x to the left, all other terms to the right

36x=75

x=75/36

x=2+1/12

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