(x-yi)(3+2i)=12-5i

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Solution for (x-yi)(3+2i)=12-5i equation: 


Simplifying
(x + -1yi)(3 + 2i) = 12 + -5i

Reorder the terms:
(-1iy + x)(3 + 2i) = 12 + -5i

Multiply (-1iy + x) * (3 + 2i)
(-1iy * (3 + 2i) + x(3 + 2i)) = 12 + -5i
((3 * -1iy + 2i * -1iy) + x(3 + 2i)) = 12 + -5i
((-3iy + -2i2y) + x(3 + 2i)) = 12 + -5i
(-3iy + -2i2y + (3 * x + 2i * x)) = 12 + -5i

Reorder the terms:
(-3iy + -2i2y + (2ix + 3x)) = 12 + -5i
(-3iy + -2i2y + (2ix + 3x)) = 12 + -5i

Reorder the terms:
(2ix + -3iy + -2i2y + 3x) = 12 + -5i
(2ix + -3iy + -2i2y + 3x) = 12 + -5i

Solving
2ix + -3iy + -2i2y + 3x = 12 + -5i

Solving for variable 'i'.

Reorder the terms:
-12 + 5i + 2ix + -3iy + -2i2y + 3x = 12 + -5i + -12 + 5i

Reorder the terms:
-12 + 5i + 2ix + -3iy + -2i2y + 3x = 12 + -12 + -5i + 5i

Combine like terms: 12 + -12 = 0
-12 + 5i + 2ix + -3iy + -2i2y + 3x = 0 + -5i + 5i
-12 + 5i + 2ix + -3iy + -2i2y + 3x = -5i + 5i

Combine like terms: -5i + 5i = 0
-12 + 5i + 2ix + -3iy + -2i2y + 3x = 0

The solution to this equation could not be determined.

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