7(x+4)-3(x+1)=4(x-2)

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Solution for 7(x+4)-3(x+1)=4(x-2) equation:


Simplifying
7(x + 4) + -3(x + 1) = 4(x + -2)

Reorder the terms:
7(4 + x) + -3(x + 1) = 4(x + -2)
(4 * 7 + x * 7) + -3(x + 1) = 4(x + -2)
(28 + 7x) + -3(x + 1) = 4(x + -2)

Reorder the terms:
28 + 7x + -3(1 + x) = 4(x + -2)
28 + 7x + (1 * -3 + x * -3) = 4(x + -2)
28 + 7x + (-3 + -3x) = 4(x + -2)

Reorder the terms:
28 + -3 + 7x + -3x = 4(x + -2)

Combine like terms: 28 + -3 = 25
25 + 7x + -3x = 4(x + -2)

Combine like terms: 7x + -3x = 4x
25 + 4x = 4(x + -2)

Reorder the terms:
25 + 4x = 4(-2 + x)
25 + 4x = (-2 * 4 + x * 4)
25 + 4x = (-8 + 4x)

Add '-4x' to each side of the equation.
25 + 4x + -4x = -8 + 4x + -4x

Combine like terms: 4x + -4x = 0
25 + 0 = -8 + 4x + -4x
25 = -8 + 4x + -4x

Combine like terms: 4x + -4x = 0
25 = -8 + 0
25 = -8

Solving
25 = -8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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