(x-9)/5=(x+1)/7

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Solution for (x-9)/5=(x+1)/7 equation: 



(x-9)/5=(x+1)/7

We move all terms to the left:

(x-9)/5-((x+1)/7)=0

We calculate fractions


x/()+(-((x+1)*5)/()=0



We calculate terms in parentheses: +(-((x+1)*5)/(), so:

-((x+1)*5)/(

We multiply all the terms by the denominator


-((x+1)*5)



We calculate terms in parentheses: -((x+1)*5), so:

(x+1)*5

We multiply parentheses

5x+5

Back to the equation:

-(5x+5)



We get rid of parentheses

-5x-5

Back to the equation:

+(-5x-5)



We get rid of parentheses

x/()-5x-5=0

We multiply all the terms by the denominator


x-5x*()-5*()=0

We add all the numbers together, and all the variables

x-5x*()=0

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