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3(x+1)+9=2(x+4)
We move all terms to the left:
3(x+1)+9-(2(x+4))=0
We multiply parentheses
3x-(2(x+4))+3+9=0
We calculate terms in parentheses: -(2(x+4)), so:We add all the numbers together, and all the variables
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
3x-(2x+8)+12=0
We get rid of parentheses
3x-2x-8+12=0
We add all the numbers together, and all the variables
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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