(x-8)/(7+x)=-1/5

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Solution for (x-8)/(7+x)=-1/5 equation: 



(x-8)/(7+x)=-1/5

We move all terms to the left:

(x-8)/(7+x)-(-1/5)=0



Domain of the equation: (7+x)!=0

We move all terms containing x to the left, all other terms to the right

x!=-7

x∈R



We add all the numbers together, and all the variables

(x-8)/(x+7)-(-1/5)=0

We get rid of parentheses

(x-8)/(x+7)+1/5=0

We calculate fractions


(5x-40)/(5x+35)+(1*(x+7))/(5x+35)=0



We calculate terms in parentheses: +(1*(x+7))/(5x+35), so:

1*(x+7))/(5x+35

We multiply all the terms by the denominator


1*(x+7))+35*(5x

Back to the equation:

+(1*(x+7))+35*(5x)



Wy multiply elements

(5x-40)/(5x+35)+(1*(x+7))+175x=0

We multiply all the terms by the denominator


(5x-40)+((1*(x+7)))*(5x+35)+175x*(5x+35)=0



We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35



We multiply parentheses

875x^2+(5x-40)+((1*(x+7)))*(5x+35)+6125x=0

We get rid of parentheses

875x^2+5x+((1*(x+7)))*(5x+35)+6125x-40=0



We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35



We add all the numbers together, and all the variables

875x^2+6130x+((1*(x+7)))*(5x+35)-40=0



We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5x+35), so:

(1*(x+7)))*(5x+35





We calculate terms in parentheses: +((1*(x+7)))*(5

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