(x-5)2+(2x+3)2=(x+1)2+97

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Solution for (x-5)2+(2x+3)2=(x+1)2+97 equation: 



(x-5)2+(2x+3)2=(x+1)2+97

We move all terms to the left:

(x-5)2+(2x+3)2-((x+1)2+97)=0

We multiply parentheses

2x+4x-((x+1)2+97)-10+6=0



We calculate terms in parentheses: -((x+1)2+97), so:

(x+1)2+97

We multiply parentheses

2x+2+97

We add all the numbers together, and all the variables

2x+99

Back to the equation:

-(2x+99)



We add all the numbers together, and all the variables

6x-(2x+99)-4=0

We get rid of parentheses

6x-2x-99-4=0

We add all the numbers together, and all the variables

4x-103=0

We move all terms containing x to the left, all other terms to the right

4x=103

x=103/4

x=25+3/4

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