(n+4)+n(n+2)=0

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Solution for (n+4)+n(n+2)=0 equation: 



(n+4)+n(n+2)=0

We multiply parentheses

n^2+(n+4)+2n=0

We get rid of parentheses

n^2+n+2n+4=0

We add all the numbers together, and all the variables

n^2+3n+4=0

a = 1; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·1·4
Δ = -7
Delta is less than zero, so there is no solution for the equation

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