(x-5)(x-5)=(x)(x)-7(x-7)

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Solution for (x-5)(x-5)=(x)(x)-7(x-7) equation: 



(x-5)(x-5)=(x)(x)-7(x-7)

We move all terms to the left:

(x-5)(x-5)-((x)(x)-7(x-7))=0

We multiply parentheses ..

(+x^2-5x-5x+25)-(xx-7(x-7))=0



We calculate terms in parentheses: -(xx-7(x-7)), so:

xx-7(x-7)

We multiply parentheses

xx-7x+49

We add all the numbers together, and all the variables

-7x+xx+49

Back to the equation:

-(-7x+xx+49)



We get rid of parentheses

x^2-5x-5x+7x-xx+25-49=0

We add all the numbers together, and all the variables

x^2-3x-xx-24=0

We move all terms containing x to the left, all other terms to the right

x^2-3x-xx=24

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