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(x-5)(x-5)=(x)(x)
We move all terms to the left:
(x-5)(x-5)-((x)(x))=0
determiningTheFunctionDomain (x-5)(x-5)-xx=0
We multiply parentheses ..
(+x^2-5x-5x+25)-xx=0
We get rid of parentheses
x^2-5x-5x-xx+25=0
We add all the numbers together, and all the variables
x^2-10x-xx+25=0
We move all terms containing x to the left, all other terms to the right
x^2-10x-xx=-25
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