(x-40)+(x-20)+(x/2-10)=180

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Solution for (x-40)+(x-20)+(x/2-10)=180 equation: 



(x-40)+(x-20)+(x/2-10)=180

We move all terms to the left:

(x-40)+(x-20)+(x/2-10)-(180)=0

We get rid of parentheses

x+x+x/2-40-20-10-180=0

We multiply all the terms by the denominator


x*2+x*2+x-40*2-20*2-10*2-180*2=0

We add all the numbers together, and all the variables

x+x*2+x*2-500=0

Wy multiply elements

x+2x+2x-500=0

We add all the numbers together, and all the variables

5x-500=0

We move all terms containing x to the left, all other terms to the right

5x=500

x=500/5

x=100

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