5+(6/5)n-9)=14

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Solution for 5+(6/5)n-9)=14 equation: 



5+(6/5)n-9)=14

We move all terms to the left:

5+(6/5)n-9)-(14)=0



Domain of the equation: 5)n!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+6/5)n+5-9)-14=0

We add all the numbers together, and all the variables

(+6/5)n=0

We multiply parentheses

6n^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{12}=0$

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