(x-4)+3x=3-(2x+3(x-5))

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Solution for (x-4)+3x=3-(2x+3(x-5)) equation: 



(x-4)+3x=3-(2x+3(x-5))

We move all terms to the left:

(x-4)+3x-(3-(2x+3(x-5)))=0

We add all the numbers together, and all the variables

3x+(x-4)-(3-(2x+3(x-5)))=0

We get rid of parentheses

3x+x-(3-(2x+3(x-5)))-4=0



We calculate terms in parentheses: -(3-(2x+3(x-5))), so:

3-(2x+3(x-5))

determiningTheFunctionDomain
-(2x+3(x-5))+3



We calculate terms in parentheses: -(2x+3(x-5)), so:

2x+3(x-5)

We multiply parentheses

2x+3x-15

We add all the numbers together, and all the variables

5x-15

Back to the equation:

-(5x-15)



We get rid of parentheses

-5x+15+3

We add all the numbers together, and all the variables

-5x+18

Back to the equation:

-(-5x+18)



We add all the numbers together, and all the variables

4x-(-5x+18)-4=0

We get rid of parentheses

4x+5x-18-4=0

We add all the numbers together, and all the variables

9x-22=0

We move all terms containing x to the left, all other terms to the right

9x=22

x=22/9

x=2+4/9

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