u(u-5)+8u=u(u+2)-2

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Solution for u(u-5)+8u=u(u+2)-2 equation: 



u(u-5)+8u=u(u+2)-2

We move all terms to the left:

u(u-5)+8u-(u(u+2)-2)=0

We add all the numbers together, and all the variables

8u+u(u-5)-(u(u+2)-2)=0

We multiply parentheses

u^2+8u-5u-(u(u+2)-2)=0



We calculate terms in parentheses: -(u(u+2)-2), so:

u(u+2)-2

We multiply parentheses

u^2+2u-2

Back to the equation:

-(u^2+2u-2)



We add all the numbers together, and all the variables

u^2+3u-(u^2+2u-2)=0

We get rid of parentheses

u^2-u^2+3u-2u+2=0

We add all the numbers together, and all the variables

u+2=0

We move all terms containing u to the left, all other terms to the right

u=-2

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