(x-3)/2x=(2x-10)/2x

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Solution for (x-3)/2x=(2x-10)/2x equation: 



(x-3)/2x=(2x-10)/2x

We move all terms to the left:

(x-3)/2x-((2x-10)/2x)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(x-3)*2x)/4x^2+(-((2x-10)*2x)/4x^2=0

We calculate fractions


((x-3)*2x)*4x^2)/(4x^2+(*4x^2)+(-((2x-10)*2x)*4x^2)/(4x^2+(*4x^2)=0



We calculate terms in parentheses: +(-((2x-10)*2x)*4x^2)/(4x^2+(*4x^2), so:

-((2x-10)*2x)*4x^2)/(4x^2+(*4x^2

We multiply all the terms by the denominator


-((2x-10)*2x)*4x^2)+((*4x^2)*(4x^2

Back to the equation:

+(-((2x-10)*2x)*4x^2)+((*4x^2)*(4x^2)



We get rid of parentheses

((x-3)*2x)*4x^2)/(4x^2+*4x^2+(-((2x-10)*2x)*4x^2)+((*4x^2)*4x^2=0

We multiply all the terms by the denominator


((x-3)*2x)*4x^2)+(*4x^2)*(4x^2+((-((2x-10)*2x)*4x^2))*(4x^2+(((*4x^2)*4x^2)*(4x^2=0

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