5(z+4)=-2(3-z)

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Solution for 5(z+4)=-2(3-z) equation: 



5(z+4)=-2(3-z)

We move all terms to the left:

5(z+4)-(-2(3-z))=0

We add all the numbers together, and all the variables

5(z+4)-(-2(-1z+3))=0

We multiply parentheses

5z-(-2(-1z+3))+20=0



We calculate terms in parentheses: -(-2(-1z+3)), so:

-2(-1z+3)

We multiply parentheses

2z-6

Back to the equation:

-(2z-6)



We get rid of parentheses

5z-2z+6+20=0

We add all the numbers together, and all the variables

3z+26=0

We move all terms containing z to the left, all other terms to the right

3z=-26

z=-26/3

z=-8+2/3

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