(x-3)/(x+1)=2-(3/x)

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Solution for (x-3)/(x+1)=2-(3/x) equation:


D( x )

x = 0

x+1 = 0

x = 0

x = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:0) U (0:+oo)

(x-3)/(x+1) = 2-(3/x) // - 2-(3/x)

(x-3)/(x+1)+3/x-2 = 0

(x*(x-3))/(x*(x+1))+(3*(x+1))/(x*(x+1))+(-2*x*(x+1))/(x*(x+1)) = 0

x*(x-3)+3*(x+1)-2*x*(x+1) = 0

x^2-2*x^2-2*x+3 = 0

3-x^2-2*x = 0

3-x^2-2*x = 0

3-x^2-2*x = 0

DELTA = (-2)^2-(-1*3*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(-1*2) or x = (2-16^(1/2))/(-1*2)

x = -3 or x = 1

(x+3)*(x-1) = 0

((x+3)*(x-1))/(x*(x+1)) = 0

((x+3)*(x-1))/(x*(x+1)) = 0 // * x*(x+1)

(x+3)*(x-1) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -3, 1 }

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