(t-3)/(t+1)=2-(3/t)

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Solution for (t-3)/(t+1)=2-(3/t) equation:


D( t )

t+1 = 0

t = 0

t+1 = 0

t+1 = 0

t+1 = 0 // - 1

t = -1

t = 0

t = 0

t in (-oo:-1) U (-1:0) U (0:+oo)

(t-3)/(t+1) = 2-(3/t) // - 2-(3/t)

(t-3)/(t+1)+3/t-2 = 0

(t*(t-3))/(t*(t+1))+(3*(t+1))/(t*(t+1))+(-2*t*(t+1))/(t*(t+1)) = 0

t*(t-3)+3*(t+1)-2*t*(t+1) = 0

t^2-2*t^2-2*t+3 = 0

3-t^2-2*t = 0

3-t^2-2*t = 0

3-t^2-2*t = 0

DELTA = (-2)^2-(-1*3*4)

DELTA = 16

DELTA > 0

t = (16^(1/2)+2)/(-1*2) or t = (2-16^(1/2))/(-1*2)

t = -3 or t = 1

(t+3)*(t-1) = 0

((t+3)*(t-1))/(t*(t+1)) = 0

((t+3)*(t-1))/(t*(t+1)) = 0 // * t*(t+1)

(t+3)*(t-1) = 0

( t+3 )

t+3 = 0 // - 3

t = -3

( t-1 )

t-1 = 0 // + 1

t = 1

t in { -3, 1 }

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