(x-3)-2(x-5)=6(x-2)

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Solution for (x-3)-2(x-5)=6(x-2) equation: 



(x-3)-2(x-5)=6(x-2)

We move all terms to the left:

(x-3)-2(x-5)-(6(x-2))=0

We multiply parentheses

(x-3)-2x-(6(x-2))+10=0

We get rid of parentheses

x-2x-(6(x-2))-3+10=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

-1x-(6x-12)+7=0

We get rid of parentheses

-1x-6x+12+7=0

We add all the numbers together, and all the variables

-7x+19=0

We move all terms containing x to the left, all other terms to the right

-7x=-19

x=-19/-7

x=2+5/7

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