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5x(4x-32)=
We move all terms to the left:
5x(4x-32)-()=0
We add all the numbers together, and all the variables
5x(4x-32)=0
We multiply parentheses
20x^2-160x=0
a = 20; b = -160; c = 0;
Δ = b2-4ac
Δ = -1602-4·20·0
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25600}=160$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-160}{2*20}=\frac{0}{40} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+160}{2*20}=\frac{320}{40} =8 $
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