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(x-3)(x-3)=-4x
We move all terms to the left:
(x-3)(x-3)-(-4x)=0
We get rid of parentheses
(x-3)(x-3)+4x=0
We multiply parentheses ..
(+x^2-3x-3x+9)+4x=0
We get rid of parentheses
x^2-3x-3x+4x+9=0
We add all the numbers together, and all the variables
x^2-2x+9=0
a = 1; b = -2; c = +9;
Δ = b2-4ac
Δ = -22-4·1·9
Δ = -32
Delta is less than zero, so there is no solution for the equation
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