6(m+3)=2m+58

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Solution for 6(m+3)=2m+58 equation: 



6(m+3)=2m+58

We move all terms to the left:

6(m+3)-(2m+58)=0

We multiply parentheses

6m-(2m+58)+18=0

We get rid of parentheses

6m-2m-58+18=0

We add all the numbers together, and all the variables

4m-40=0

We move all terms containing m to the left, all other terms to the right

4m=40

m=40/4

m=10

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