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(x-3)(x+5)=(x*x)-7x-6
We move all terms to the left:
(x-3)(x+5)-((x*x)-7x-6)=0
We add all the numbers together, and all the variables
(x-3)(x+5)-((+x*x)-7x-6)=0
We multiply parentheses ..
(+x^2+5x-3x-15)-((+x*x)-7x-6)=0
We calculate terms in parentheses: -((+x*x)-7x-6), so:We get rid of parentheses
(+x*x)-7x-6
We add all the numbers together, and all the variables
-7x+(+x*x)-6
We get rid of parentheses
-7x+x*x-6
Wy multiply elements
x^2-7x-6
Back to the equation:
-(x^2-7x-6)
x^2-x^2+5x-3x+7x-15+6=0
We add all the numbers together, and all the variables
9x-9=0
We move all terms containing x to the left, all other terms to the right
9x=9
x=9/9
x=1
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