6(t-5)-3(t+3)=4t+11

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Solution for 6(t-5)-3(t+3)=4t+11 equation: 



6(t-5)-3(t+3)=4t+11

We move all terms to the left:

6(t-5)-3(t+3)-(4t+11)=0

We multiply parentheses

6t-3t-(4t+11)-30-9=0

We get rid of parentheses

6t-3t-4t-11-30-9=0

We add all the numbers together, and all the variables

-1t-50=0

We move all terms containing t to the left, all other terms to the right

-t=50

t=50/-1

t=-50

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