(x-3)(x+2)=(x+5)(x-1)

Solution for (x-3)(x+2)=(x+5)(x-1) equation:

(x-3)(x+2)=(x+5)(x-1)

We move all terms to the left:

(x-3)(x+2)-((x+5)(x-1))=0

We multiply parentheses ..

(+x^2+2x-3x-6)-((x+5)(x-1))=0


We calculate terms in parentheses: -((x+5)(x-1)), so:

(x+5)(x-1)

We multiply parentheses ..

(+x^2-1x+5x-5)

We get rid of parentheses

x^2-1x+5x-5

We add all the numbers together, and all the variables

x^2+4x-5

Back to the equation:

-(x^2+4x-5)


We get rid of parentheses

x^2-x^2+2x-3x-4x-6+5=0

We add all the numbers together, and all the variables

-5x-1=0

We move all terms containing x to the left, all other terms to the right

-5x=1

x=1/-5

x=-1/5