7-(x-3)2=6x+23

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Solution for 7-(x-3)2=6x+23 equation: 



7-(x-3)2=6x+23

We move all terms to the left:

7-(x-3)2-(6x+23)=0

We multiply parentheses

-2x-(6x+23)+6+7=0

We get rid of parentheses

-2x-6x-23+6+7=0

We add all the numbers together, and all the variables

-8x-10=0

We move all terms containing x to the left, all other terms to the right

-8x=10

x=10/-8

x=-1+1/4

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