(x-3)(x+1)(x+4)=0

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Solution for (x-3)(x+1)(x+4)=0 equation: 


Simplifying
(x + -3)(x + 1)(x + 4) = 0

Reorder the terms:
(-3 + x)(x + 1)(x + 4) = 0

Reorder the terms:
(-3 + x)(1 + x)(x + 4) = 0

Reorder the terms:
(-3 + x)(1 + x)(4 + x) = 0

Multiply (-3 + x) * (1 + x)
(-3(1 + x) + x(1 + x))(4 + x) = 0
((1 * -3 + x * -3) + x(1 + x))(4 + x) = 0
((-3 + -3x) + x(1 + x))(4 + x) = 0
(-3 + -3x + (1 * x + x * x))(4 + x) = 0
(-3 + -3x + (1x + x2))(4 + x) = 0

Combine like terms: -3x + 1x = -2x
(-3 + -2x + x2)(4 + x) = 0

Multiply (-3 + -2x + x2) * (4 + x)
(-3(4 + x) + -2x * (4 + x) + x2(4 + x)) = 0
((4 * -3 + x * -3) + -2x * (4 + x) + x2(4 + x)) = 0
((-12 + -3x) + -2x * (4 + x) + x2(4 + x)) = 0
(-12 + -3x + (4 * -2x + x * -2x) + x2(4 + x)) = 0
(-12 + -3x + (-8x + -2x2) + x2(4 + x)) = 0
(-12 + -3x + -8x + -2x2 + (4 * x2 + x * x2)) = 0
(-12 + -3x + -8x + -2x2 + (4x2 + x3)) = 0

Combine like terms: -3x + -8x = -11x
(-12 + -11x + -2x2 + 4x2 + x3) = 0

Combine like terms: -2x2 + 4x2 = 2x2
(-12 + -11x + 2x2 + x3) = 0

Solving
-12 + -11x + 2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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