8u-(2u+5)=4(u+1)-13

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Solution for 8u-(2u+5)=4(u+1)-13 equation:


Simplifying
8u + -1(2u + 5) = 4(u + 1) + -13

Reorder the terms:
8u + -1(5 + 2u) = 4(u + 1) + -13
8u + (5 * -1 + 2u * -1) = 4(u + 1) + -13
8u + (-5 + -2u) = 4(u + 1) + -13

Reorder the terms:
-5 + 8u + -2u = 4(u + 1) + -13

Combine like terms: 8u + -2u = 6u
-5 + 6u = 4(u + 1) + -13

Reorder the terms:
-5 + 6u = 4(1 + u) + -13
-5 + 6u = (1 * 4 + u * 4) + -13
-5 + 6u = (4 + 4u) + -13

Reorder the terms:
-5 + 6u = 4 + -13 + 4u

Combine like terms: 4 + -13 = -9
-5 + 6u = -9 + 4u

Solving
-5 + 6u = -9 + 4u

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-4u' to each side of the equation.
-5 + 6u + -4u = -9 + 4u + -4u

Combine like terms: 6u + -4u = 2u
-5 + 2u = -9 + 4u + -4u

Combine like terms: 4u + -4u = 0
-5 + 2u = -9 + 0
-5 + 2u = -9

Add '5' to each side of the equation.
-5 + 5 + 2u = -9 + 5

Combine like terms: -5 + 5 = 0
0 + 2u = -9 + 5
2u = -9 + 5

Combine like terms: -9 + 5 = -4
2u = -4

Divide each side by '2'.
u = -2

Simplifying
u = -2

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