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(x-3)(5x+22)=(x+4)(5x-14)
We move all terms to the left:
(x-3)(5x+22)-((x+4)(5x-14))=0
We multiply parentheses ..
(+5x^2+22x-15x-66)-((x+4)(5x-14))=0
We calculate terms in parentheses: -((x+4)(5x-14)), so:We get rid of parentheses
(x+4)(5x-14)
We multiply parentheses ..
(+5x^2-14x+20x-56)
We get rid of parentheses
5x^2-14x+20x-56
We add all the numbers together, and all the variables
5x^2+6x-56
Back to the equation:
-(5x^2+6x-56)
5x^2-5x^2+22x-15x-6x-66+56=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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