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(x-2)+4x=-(x-3)
We move all terms to the left:
(x-2)+4x-(-(x-3))=0
We add all the numbers together, and all the variables
4x+(x-2)-(-(x-3))=0
We get rid of parentheses
4x+x-(-(x-3))-2=0
We calculate terms in parentheses: -(-(x-3)), so:We add all the numbers together, and all the variables
-(x-3)
We get rid of parentheses
-x+3
We add all the numbers together, and all the variables
-1x+3
Back to the equation:
-(-1x+3)
5x-(-1x+3)-2=0
We get rid of parentheses
5x+1x-3-2=0
We add all the numbers together, and all the variables
6x-5=0
We move all terms containing x to the left, all other terms to the right
6x=5
x=5/6
x=5/6
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