(x-2)+(4x-5)+(x+19)=180

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Solution for (x-2)+(4x-5)+(x+19)=180 equation: 



(x-2)+(4x-5)+(x+19)=180

We move all terms to the left:

(x-2)+(4x-5)+(x+19)-(180)=0

We get rid of parentheses

x+4x+x-2-5+19-180=0

We add all the numbers together, and all the variables

6x-168=0

We move all terms containing x to the left, all other terms to the right

6x=168

x=168/6

x=28

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