7(3a-4)-3(4a+5)-(6a+2)=a+8(4a-9)+17

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Solution for 7(3a-4)-3(4a+5)-(6a+2)=a+8(4a-9)+17 equation: 



7(3a-4)-3(4a+5)-(6a+2)=a+8(4a-9)+17

We move all terms to the left:

7(3a-4)-3(4a+5)-(6a+2)-(a+8(4a-9)+17)=0

We multiply parentheses

21a-12a-(6a+2)-(a+8(4a-9)+17)-28-15=0

We get rid of parentheses

21a-12a-6a-(a+8(4a-9)+17)-2-28-15=0



We calculate terms in parentheses: -(a+8(4a-9)+17), so:

a+8(4a-9)+17

We multiply parentheses

a+32a-72+17

We add all the numbers together, and all the variables

33a-55

Back to the equation:

-(33a-55)



We add all the numbers together, and all the variables

3a-(33a-55)-45=0

We get rid of parentheses

3a-33a+55-45=0

We add all the numbers together, and all the variables

-30a+10=0

We move all terms containing a to the left, all other terms to the right

-30a=-10

a=-10/-30

a=1/3

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