(x-2)*(x+3)=(x-1)*(x+4)

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Solution for (x-2)*(x+3)=(x-1)*(x+4) equation: 



(x-2)(x+3)=(x-1)(x+4)

We move all terms to the left:

(x-2)(x+3)-((x-1)(x+4))=0

We multiply parentheses ..

(+x^2+3x-2x-6)-((x-1)(x+4))=0



We calculate terms in parentheses: -((x-1)(x+4)), so:

(x-1)(x+4)

We multiply parentheses ..

(+x^2+4x-1x-4)

We get rid of parentheses

x^2+4x-1x-4

We add all the numbers together, and all the variables

x^2+3x-4

Back to the equation:

-(x^2+3x-4)



We get rid of parentheses

x^2-x^2+3x-2x-3x-6+4=0

We add all the numbers together, and all the variables

-2x-2=0

We move all terms containing x to the left, all other terms to the right

-2x=2

x=2/-2

x=-1

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