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3(x+1)=4(2x-8)
We move all terms to the left:
3(x+1)-(4(2x-8))=0
We multiply parentheses
3x-(4(2x-8))+3=0
We calculate terms in parentheses: -(4(2x-8)), so:We get rid of parentheses
4(2x-8)
We multiply parentheses
8x-32
Back to the equation:
-(8x-32)
3x-8x+32+3=0
We add all the numbers together, and all the variables
-5x+35=0
We move all terms containing x to the left, all other terms to the right
-5x=-35
x=-35/-5
x=+7
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