(x-2)(x-5)=(x-1)(x+6)

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Solution for (x-2)(x-5)=(x-1)(x+6) equation: 



(x-2)(x-5)=(x-1)(x+6)

We move all terms to the left:

(x-2)(x-5)-((x-1)(x+6))=0

We multiply parentheses ..

(+x^2-5x-2x+10)-((x-1)(x+6))=0



We calculate terms in parentheses: -((x-1)(x+6)), so:

(x-1)(x+6)

We multiply parentheses ..

(+x^2+6x-1x-6)

We get rid of parentheses

x^2+6x-1x-6

We add all the numbers together, and all the variables

x^2+5x-6

Back to the equation:

-(x^2+5x-6)



We get rid of parentheses

x^2-x^2-5x-2x-5x+10+6=0

We add all the numbers together, and all the variables

-12x+16=0

We move all terms containing x to the left, all other terms to the right

-12x=-16

x=-16/-12

x=1+1/3

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