(5y+20+3y=-20)

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Solution for (5y+20+3y=-20) equation: 



(5y+20+3y=-20)

We move all terms to the left:

(5y+20+3y-(-20))=0



We calculate terms in parentheses: +(5y+20+3y-(-20)), so:

5y+20+3y-(-20)

determiningTheFunctionDomain
5y+3y+20-(-20)

We add all the numbers together, and all the variables

8y+40

Back to the equation:

+(8y+40)



We get rid of parentheses

8y+40=0

We move all terms containing y to the left, all other terms to the right

8y=-40

y=-40/8

y=-5

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