(x-2)(x-4)+9=0

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Solution for (x-2)(x-4)+9=0 equation: 



(x-2)(x-4)+9=0

We multiply parentheses ..

(+x^2-4x-2x+8)+9=0

We get rid of parentheses

x^2-4x-2x+8+9=0

We add all the numbers together, and all the variables

x^2-6x+17=0

a = 1; b = -6; c = +17;
Δ = b2-4ac
Δ = -62-4·1·17
Δ = -32
Delta is less than zero, so there is no solution for the equation

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