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(3x+4)(x)=360
We move all terms to the left:
(3x+4)(x)-(360)=0
We multiply parentheses
3x^2+4x-360=0
a = 3; b = 4; c = -360;
Δ = b2-4ac
Δ = 42-4·3·(-360)
Δ = 4336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4336}=\sqrt{16*271}=\sqrt{16}*\sqrt{271}=4\sqrt{271}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{271}}{2*3}=\frac{-4-4\sqrt{271}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{271}}{2*3}=\frac{-4+4\sqrt{271}}{6} $
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