(x-2)(x-3)=x(x-4)

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Solution for (x-2)(x-3)=x(x-4) equation: 



(x-2)(x-3)=x(x-4)

We move all terms to the left:

(x-2)(x-3)-(x(x-4))=0

We multiply parentheses ..

(+x^2-3x-2x+6)-(x(x-4))=0



We calculate terms in parentheses: -(x(x-4)), so:

x(x-4)

We multiply parentheses

x^2-4x

Back to the equation:

-(x^2-4x)



We get rid of parentheses

x^2-x^2-3x-2x+4x+6=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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