(x-2)(x+1)=(x-3)(x+4)

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Solution for (x-2)(x+1)=(x-3)(x+4) equation: 



(x-2)(x+1)=(x-3)(x+4)

We move all terms to the left:

(x-2)(x+1)-((x-3)(x+4))=0

We multiply parentheses ..

(+x^2+x-2x-2)-((x-3)(x+4))=0



We calculate terms in parentheses: -((x-3)(x+4)), so:

(x-3)(x+4)

We multiply parentheses ..

(+x^2+4x-3x-12)

We get rid of parentheses

x^2+4x-3x-12

We add all the numbers together, and all the variables

x^2+x-12

Back to the equation:

-(x^2+x-12)



We get rid of parentheses

x^2-x^2+x-2x-x-2+12=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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